Using Grep and Awk to find a quoted string in code using a partial string
The following script will find all occurrences of a partial string. Print out the whole string and the file name and line number.
Scripts must be placed in the root directory, otherwise use the full path names.
1) First a script to find the regex matches
#!/bin/bash -f searchString1='\"usp_.*\"' searchString2='.usp_' # Path grep -iR -e $searchString1 -e $searchString2 "./Main Line">all_usp.txt
2) Optional a script to tidy up the output
#!/bin/bash -f # remove tabs tr -d " \t" <all_usp.txt>all_usp_temp.txt # extract filename and usp name cat all_usp_temp.txt| awk -F'[:"]' 'match($0,/usp_.*"/) {print $1 "\t" substr($0,RSTART,RLENGTH)}'|awk -F'[:"]' '{print $1 "\t" $2}'|sort -u>all_usp_final.txt # if required convert to dos unix2dos all_usp_final.txt
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